10n^2+95n+45=0

Solution for 10n^2+95n+45=0 equation:

10n^2+95n+45=0

a = 10; b = 95; c = +45;
Δ = b2-4ac
Δ = 952-4·10·45
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-85}{2*10}=\frac{-180}{20}
=-9
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+85}{2*10}=\frac{-10}{20}
=-1/2
$